Wiki User
∙ 14y ago3 / 12 = 0.25 miles/second2.
Wiki User
∙ 14y agoSo it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
Speed = (initial speed) plus (acceleration) x (time) = 0 + (5) x (3) = 15 meters per second.
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
Magnitude of average acceleration = (change of speed) divided by (time for the change)Average 'A' = (6 - 4) / 20 = 2/20 = 0.1 meter per second2-- That's the average over the 20 seconds. We don't know anything about thevalue of the acceleration at any particular instant during the 20 seconds.-- We're working entirely with scalars ... speed, not velocity, and magnitude ofacceleration ... since we don't know anything about the runner's direction atany time during the whole event.
Average acceleration is the amount of acceleration per unit of time that a thing or an object undergoes. It is simple to discover. To find the average acceleration, we need only find out how much acceleration occurred and over what period of time. If we have the starting and the ending speeds, then by subtracting them we can find the chane of acceleration. Then we can divide that acceleration by the time it took to occur. The eagle in our example accelerates from 15 m/s to 22 m/s over a period of 4 seconds. His total acceleration was 7 m/s (22 m/s minus 15 m/s = 7 m/s), and, since it took 4 seconds to increase his speed by 7 m/s, the average acceleration is the total acceleration divided by the time it took to happen (as was stated). The average acceleration is 7 m/s divided by 4 seconds or 1.75 meters per second.
The acceleration of the body is 3 m/s²
So acceleration is an increase of speed every second. The increase of speed was 9miles/sec and this was over 3 seconds. Therefore there was an acceleration of 3 miles/second every second i.e. 3m/s2
5 metres per second squared
3 m/s2
It is 0.1 metre per second-squared.
60.912 meters in that time
The runner's acceleration can be calculated using the formula a = Δv/t, where Δv is the change in velocity (11 m/s - 0 m/s = 11 m/s) and t is the time taken (5 seconds). Therefore, the acceleration is 11 m/s divided by 5 seconds, which equals 2.2 m/s².
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
Speed = (initial speed) plus (acceleration) x (time) = 0 + (5) x (3) = 15 meters per second.
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
It is 0.1 metre per second-squared.
Magnitude of average acceleration = (change of speed) divided by (time for the change)Average 'A' = (6 - 4) / 20 = 2/20 = 0.1 meter per second2-- That's the average over the 20 seconds. We don't know anything about thevalue of the acceleration at any particular instant during the 20 seconds.-- We're working entirely with scalars ... speed, not velocity, and magnitude ofacceleration ... since we don't know anything about the runner's direction atany time during the whole event.