With variables, all you have to do is replace any variable with what it is equal to:
Example:
A + B = C
If A = 5 and B = 10
Just replace every A with a 5 (because A = 5)
5 + B = C
Then just replace every B with a 10 (because B = 10)
5 + 10 = C
Then you can solve for C.
5 + 10 = 15
Therefore C = 15
For your Problem, you have:
(5)(r) + 1 = ??? given that r = 3
Replace every r with a 3 (because r = 3)
(5)(3) + 1 = ???
Use your order of operations: PEMDAS, so multiply the two numbers first
15 + 1 = 16
The answer is 5r+1 = 16, when r is equal to 3
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
When you are using non-standard definitions of "plus" and "minus", or of "equal".
It is: 1/3 plus 1/3 = 2/3
3+10-r+6r = -3+9r+0 13+5r = -3+9r 16 = 4r r = 4
No, 1 + 2 + 3 + 4 + 5 = 15.
1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
-1
multiply r2+7r+10/3 by 3r-30/r2-5r-50 weegy
First, translate it into an algebraic equation:4 + 5r = -11Then we subtract 4 from both sides:4 + 5r - 4 = -11 - 4Now we can simplify our numbers together:(4 - 4) + 5r = -11 - 40 + 5r = -155r = -15Now we divide both sides by 5:(5r / 5) = (-15 / 5)r = -3
They both are the same. They both equal 4.
1
-3 +1 = -2
When you are using non-standard definitions of "plus" and "minus", or of "equal".
4
It is: 1/3 plus 1/3 = 2/3
3+10-r+6r = -3+9r+0 13+5r = -3+9r 16 = 4r r = 4