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Why you use cosine theta with cross product?
Normally you use sine theta with the cross product and cos theta with the vector product, so that the cross product of parallel vectors is zero while the dot product of vectors at right angles is zero.
Dot product of two vectors is equal to cross product what will be angle between them?
(A1) The dot product of two vectors is a scalar and the cross product is a vector? ================================== (A2) The cross product of two vectors, A and B, would be [a*b*sin(alpha)]C, where a = |A|; b = |B|; c = |C|; and C is vector that is orthogonal to A and B and oriented according to the right-hand rule (see the related link). The dot product of the two vectors, A and B, would be [a*b*cos(alpha)]. For [a*b*sin(alpha)]C to equal to [a*b*cos(alpha)], we have to have a trivial solution -- alpha = 0 and either a or b be zero, so that both expressions are zeroes but equal. ================================== Of course one is the number zero( scalar), and one is the zero vector. It is a small difference but worth mentioning. That is is to say if a or b is the zero vector, then a dot b must equal zero as a scalar. And similarly the cross product of any vector and the zero vector is the zero vector. (A3) The magnitude of the dot product is equal to the magnitude of the cross product when the angle between the vectors is 45 degrees.
How do you get product of the zero?
multiply anything by zero and your product will be zero!
What is the product of zero and any number?
The product of zero and any number is always 0.
What is the product of the ten 1-digit numbers?
If you're including zero, the product is zero.
Why you use cosine theta with cross product?
Normally you use sine theta with the cross product and cos theta with the vector product, so that the cross product of parallel vectors is zero while the dot product of vectors at right angles is zero.
If AxB is zero and A and B are non zero then prove that A is parallel to B?
If A and B are vectors then AxB=ABsin(AB). If A and B are not zero then AxB is zero if and only if sin(AB)=0 meaning the angle between A and B is a multiple of 180 degrees, in other words parallel.
Dot product of two vectors is equal to cross product what will be angle between them?
(A1) The dot product of two vectors is a scalar and the cross product is a vector? ================================== (A2) The cross product of two vectors, A and B, would be [a*b*sin(alpha)]C, where a = |A|; b = |B|; c = |C|; and C is vector that is orthogonal to A and B and oriented according to the right-hand rule (see the related link). The dot product of the two vectors, A and B, would be [a*b*cos(alpha)]. For [a*b*sin(alpha)]C to equal to [a*b*cos(alpha)], we have to have a trivial solution -- alpha = 0 and either a or b be zero, so that both expressions are zeroes but equal. ================================== Of course one is the number zero( scalar), and one is the zero vector. It is a small difference but worth mentioning. That is is to say if a or b is the zero vector, then a dot b must equal zero as a scalar. And similarly the cross product of any vector and the zero vector is the zero vector. (A3) The magnitude of the dot product is equal to the magnitude of the cross product when the angle between the vectors is 45 degrees.
How do you get product of the zero?
multiply anything by zero and your product will be zero!
What are different conditions that could make vector product zero?
The vector product (cross product) of two vectors will be zero when the vectors are parallel or antiparallel to each other. This means the vectors are either pointing in the same direction (parallel) or in opposite directions (antiparallel).
When is a cross product zero?
When the component vectors have equal or opposite directions (sin(Θ) = 0) i.e. the vectors are parallel.
If a particle moves in a straight line is its angular momentum zero with respect to any arbitary acis?
Yes, for a particle moving in a straight line, its angular momentum is zero with respect to any arbitrary axis. This is because angular momentum is defined as the cross product of the position vector and momentum vector of the particle, and since they lie along the same line for straight-line motion, the cross product will result in zero.
When you use cross product and dot product in vector?
Dot product and cross product are used in many cases in physics. Here are some examples:Work is sometimes defined as force times distance. However, if the force is not applied in the direction of the movement, the dot product should be used. Note that here - as well as in other cases where the dot product is used - the product is greatest when the angle is zero; also, the result is a scalar, not a vector.The cross product is used to define torque (distance from the axis of rotation, times force). In this case, the product is greatest when the two vectors are at right angles. Also - as in any cross product - the result is also a vector.Several interactions between electricity and magnetism are defined as cross products.
What is the product of the ten 1-digit numbers?
If you're including zero, the product is zero.
What is the product of zero and any number?
The product of zero and any number is always 0.
What is the cross product of a vector itself?
0 is a cross product of a vector itself
What is the product of a number and zero?
A number multiplied by zero equals zero.
