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Q: When did December last have 5 sat and 5 sun and 5 mon?
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Continue Learning about Math & Arithmetic

When did July last have 5 sat and 5 sun 5 mon?

As of 2011, the last time the month of July contained five Saturdays, Sundays, and Mondays was in 2006. The next time it will happen is in 2017.


What is the probability of getting 53 Sunday in a leap year?

Total number of days in a leap year is 366, ie 52 weeks and 2 days. The last 2 days can be either ( Mon Tue, Tue Wed, Wed Thu, Thu Fri, Fri Sat, Sat Sun, Sun Mon) The possible outcomes are 7 The outcomes where one of the day is a Sunday is 2 So probability of getting 53 Sundays is = 2/7. The exact probability is 28/97, which is about 28.87%.


When was the last time there were 5 Fri 5 Sat 5 Sun and 5 Mon in a month?

That has never happened, and ... without a significant change in the format of our calendar ... it never will. In order to have 5 each of four consecutive days of the week, the month must have 32 days in it. Under the present system, none of them does.


How often is there 5 Fridays Saturdays and Sundays in one month?

For that to happen, the month has to be 31 days long and has to start on a Friday. Since there are 7 months with 31 days and one chance in 7 a month will start on a Friday ( roughly, due to leap years) there is about once yaer this will happen.Next month has 5 Fridays, Saturdays, and Sundays.Since14.5% of all years have a January with 5 of (Fri-Sat-Sun),14.25% of all years have a March with 5 of (Fri-Sat-Sun),14.5% of all years have a May with 5 of (Fri-Sat-Sun),14.5% of all years have a July with 5 of (Fri-Sat-Sun),14.25% of all years have an August with 5 of (Fri-Sat-Sun),14% of all years have an October with 5 of (Fri-Sat-Sun), and14% of all years have a December with 5 of (Fri-Sat-Sun),the average occurrence comes to exactly once per year.


What is the probability that a leap year selected at random will contain you 53 Sundays II 53 Thursdays?

A Leap year has 366 days. in which you have 52 weeks and 2 days. the 2 days may be sun,Mon mon,Tue tue,wed wed,THu, thu,Fri FRi,SAT sat,sun so you have 7 options among which 2 u can choose.. so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7. The probability of having either 53 Sundays or 53 Thursdays is 4/7.