Total number of days in a leap year is 366, ie 52 weeks and 2 days.
The last 2 days can be either ( Mon Tue, Tue Wed, Wed Thu, Thu Fri, Fri Sat, Sat Sun, Sun Mon)
The possible outcomes are 7
The outcomes where one of the day is a Sunday is 2
So probability of getting 53 Sundays is = 2/7.
The exact probability is 28/97, which is about 28.87%.
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The probability is very close to 0.25 A year is a leap year if the number is divisible by 4 - except if the number is divisible by 100 it is not a leap year - except if the number is divisible by 400 it is a leap year. So, in a 400-year period there are 97 leap years. The probability or relative frequency of leap years is, therefore, 97/400 = 0.2425
The total number of days in a leap year is 366. Then, if we want to determine the probability of 53 Wednesdays occurring in a leap year, we write 53 / 366.
The answer depends on where in the world you are - much more than whether or not it is a leap year. In some countries, a majority of births take place in hospitals or maternity units. Medical staff in such establishments do not like working on Saturdays and so the probability of getting a baby on a Saturday is less than 1/7.
Birthdays are not distributed uniformly over a year but if, for the sake of probability games you assume that they are, then ignoring leap years, the probability is 0.5687. Including leap years, it is slightly lower.
If today is Wednesday, it be a Saturday if there is no leap year, or a Sunday if there is a leap year, within the next 1249 days.