H. T. Muggeridge died in 1942-03.
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There are 2 outcomes for the dime (H or T), 2 for the penny (H or T) and 6 for the die (1,2,3,4,5,6). In all, there are 2*2*6 = 24 outcomes. Some of them are given below in the pattern: dime, penny, die. The rest are easy to generate. [H,H,1], [H,H,2], ... , [H,H,6], [H,T,1], [H,T,2], ... [T,H,1], ... [T,T,1], ...
0.666 ^^^^ his answer mine 3 in 8 i believe. which is 0.375 you can get h,h,h h,t,h h,t,t h,h,t t,h,h t,t,h t,h,t t,t,t the ones you are looking for are h,h,t t,h,h h,t,h
There are 8 permutations of three coins ... T T T T T H T H T T H H H T T H T H H H T H H H ... counting heads and sorting by count, you get ... 0 - T T T 1 - T T H 1 - T H T 1 - H T T 2 - T H H 2 - H T H 2 - H H T 3 - H H H ... so, the probability of each possible number of heads is 0: 1 in 8, 1: 3 in 8, 2: 3 in 8, and 3: 1 in 8.
4 : Each coin toss multiplies the generated outcome by two. The outcome for two tosses can be Heads (H) Tails (T), H H, T T or T H. As such, with three tosses the outcome can be H H H, H H T, H T H, T H H, T T H, T T T, T H T, H T T. We can define the number of outcomes as 2^n, where n is the amount of tosses.
4: h/h, h/t, t/h & t/t