You need either a point and the slope of the line or two points. Then you use the point slope form of the line or the slope intercept form to write the lines.A given point has an infinite number of lines going through it, that is why you need more information.
It is used when working out a straight line equation.
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
In the case that you are using Slope-Intercept Form, no, you only plot two points: the y-intercept and one other point. If you don't use Slope-Intercept Form, then you have to use three points.
You use standard form in algebra because you have to know the number before you answer the problem
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
You need either a point and the slope of the line or two points. Then you use the point slope form of the line or the slope intercept form to write the lines.A given point has an infinite number of lines going through it, that is why you need more information.
It is used when working out a straight line equation.
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
Point: (2, 4) Slope: -3 Equation: y = -3x+10
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
y - y1 = m (x - x1) If your point was (5,4) and your slope was 3, then the equation would look like this: y - 4 = 3 (x - 5) Then you would use distributive property to solve from there...but continueing to solve would not be point-slope form... y-4=3(x-5) would be your complete answer for a question asking to write an equation in point-slope form.
By differentiating the answer and plugging in the x value along the curve, you are finding the exact slope of the curve at that point. In effect, this would be the slope of the tangent line, as a tangent line only intersects another at one point. To find the equation of a tangent line to a curve, use the point slope form (y-y1)=m(x-x1), m being the slope. Use the differential to find the slope and use the point on the curve to plug in for (x1, y1).
In the case that you are using Slope-Intercept Form, no, you only plot two points: the y-intercept and one other point. If you don't use Slope-Intercept Form, then you have to use three points.
The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.
You use standard form in algebra because you have to know the number before you answer the problem