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If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form.

The general equation for point slope form is

Y-y1=m(x-x1)

The y1 is the y coordinate of the given point.

X1 is the x coordinate of the given point.

M is the slope that you found earlier.

You now have your equation.

If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.

Q: Find equation perpendicular to given line contain given point?

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That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.

That would depend on its slope which has not been given.

If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5

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you make an equation of the line: standard form: (y-y1)= m(x-x1) so if the point is (2, -2) and you want to make it perpendicular to the line with a slope (m) of 1/2, the perpendicular slope is the negative recipricle which is -2 so the equation would be: (y--2)= -2(x-2) (y+2)= -2(x-2) y+2= -2x +4 -2 -2 Slope Intercept Form: y= -2x +2

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That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.

That would depend on its slope which has not been given.

Yes, I could, if I knew the slope of the line given.

The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.

-1

y = -(1/5)x + 9

If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5

Without an equality sign and not knowing some of the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean: y = 12x-3 a given point of (5, 0) Then the perpendicular equation is: y = -1/12x+5/12 whereas -1/12 is the slope and 5/12 is the y intercept

Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.

The perpendicular postulate states that if there is a line, as well as a point that is not on the line, then there is exactly one line through the point that is perpendicular to the given line.

Given Point: (0,-1) Given Line: y=2x+5 If the line you are trying to find the equation of is perpendicular to the line given then the slope of the line you are trying to find must be the negative reciprocal of the line given. The slope of the line given is 2 so the slope of the line perpendicular to this one is -1/2. Using y=mx+b we get that y=(-1/2)x+b. Then we must use the point that was given to find b (the y-intercept). This means: -1=(-1/2)(0)+b -1=b So the equation is y=(-1/2)x-1

Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula