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If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form.
The general equation for point slope form is
Y-y1=m(x-x1)
The y1 is the y coordinate of the given point.
X1 is the x coordinate of the given point.
M is the slope that you found earlier.
You now have your equation.
If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
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What is the equation of a line that is perpendicular to and passes through the point (8 3)?
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
What is the equation of a line that is perpendicular to and passes through the point (4 6)?
That would depend on its slope which has not been given.
What is the equation of the line that contains the point (21) and is perpendicular to the line y3x-4?
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
How many planes can be perpendicular to a given line at a given point?
Only one
How do you write an equation that is perpendicular to a given line and passes through the given point?
you make an equation of the line: standard form: (y-y1)= m(x-x1) so if the point is (2, -2) and you want to make it perpendicular to the line with a slope (m) of 1/2, the perpendicular slope is the negative recipricle which is -2 so the equation would be: (y--2)= -2(x-2) (y+2)= -2(x-2) y+2= -2x +4 -2 -2 Slope Intercept Form: y= -2x +2
What is the equation of a line that is perpendicular to and passes through the point (8 3)?
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
What is the equation of a line that is perpendicular to and passes through the point (4 6)?
That would depend on its slope which has not been given.
Could you write the equation of the line that is perpendicular to the line given that passes through the point shown?
Yes, I could, if I knew the slope of the line given.
How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
What is the slope of a line perpendicular to 2x-y3?
-1
Find the equation of the line passing through the given point and perpendicular to the given line (5, 9); x-5y=8?
y = -(1/5)x + 9
What is the equation of the line that contains the point (21) and is perpendicular to the line y3x-4?
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
What is the slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (50) y 12 (-3)?
Without an equality sign and not knowing some of the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean: y = 12x-3 a given point of (5, 0) Then the perpendicular equation is: y = -1/12x+5/12 whereas -1/12 is the slope and 5/12 is the y intercept
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
What is the perpendicular postulate?
The perpendicular postulate states that if there is a line, as well as a point that is not on the line, then there is exactly one line through the point that is perpendicular to the given line.
What is the equation through point 0 negative 1 perpendicular to y equals 2x plus 5?
Given Point: (0,-1) Given Line: y=2x+5 If the line you are trying to find the equation of is perpendicular to the line given then the slope of the line you are trying to find must be the negative reciprocal of the line given. The slope of the line given is 2 so the slope of the line perpendicular to this one is -1/2. Using y=mx+b we get that y=(-1/2)x+b. Then we must use the point that was given to find b (the y-intercept). This means: -1=(-1/2)(0)+b -1=b So the equation is y=(-1/2)x-1
How do you get the perpendicular to the equation 4x-3y equals 7?
Write the equation of the given line in standard form: y = mx + c so: 3y = 4x - 7 or y = 4/3x - 7/3 The slope of the given line is 4/3. The slope of the line perpendicular to it is the negative reciprocal (change the sign and flip the fraction over). ie the perpendicular has slope -3/4 So the equation of the perpendicular is of the form y = -3/4x + d or 4y = - 3x + 4d or 3x + 4y = 4d. To evaluate the value of the constant d (or 4d) you will need one point on the perpendicular line. Substitute the coordinates of that point for x and y in the above equation and you've got 4d.
