a=10
14!!
We have, 2a + 24 = 30or, 2a = 30-24or, 2a = 6or, a = 6/2 = 3.Therefore, a equals 3 or simply a=3
It is a linear equation in one variable, a.
Since you have A on both sides of the equation, 2A = 24A, A must be 0, though it is more likely that you're missing a term from one side of the equation.
a=10
14!!
We have, 2a + 24 = 30or, 2a = 30-24or, 2a = 6or, a = 6/2 = 3.Therefore, a equals 3 or simply a=3
It is a linear equation in one variable, a.
If: 2a+13 = 5a+1 Then: a = 4
Since you have A on both sides of the equation, 2A = 24A, A must be 0, though it is more likely that you're missing a term from one side of the equation.
It is, in fact, an identity - which is an equation which is true for all values of the variable.
x=-b/2a [negative B over 2A]
x equals negative b plus or minus the square root of b squared minus 4bc over 2a
5a-20+2a = 6a-11 5a+2a-6a = 20-11 1a = 9 a = 9
Solve the following equation for A : 2A/3 = 8 + 4A
Let's solve this equation together, friend. To isolate b, we can start by subtracting 2a from both sides of the equation. This will leave us with b equals P minus 2a. Remember, there are many ways to approach a problem, and it's all about finding the one that works best for you.