When the elevator starts moving down, the time period increases. But when the elevator is descending at a constant velocity, the time period returns to its normal.
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
A longer pendulum has a longer period.
T=2pi(l/g)1/2
Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
Yes, the period of a pendulum is not affected by the weight of the pendulum bob. The period is determined by the length of the pendulum and the acceleration due to gravity. A heavier pendulum bob will swing with the same period as a lighter one of the same length.
Increasing the mass of a pendulum would not change the period of its oscillation. The period of a pendulum only depends on the length of the pendulum and the acceleration due to gravity, but not the mass of the pendulum bob.
a) The period of a simple pendulum on Earth depends on the acceleration due to gravity, which is approximately 9.81 m/s^2. Using the formula for the period of a pendulum, T = 2pisqrt(L/g), where L is the length of the pendulum (80 cm = 0.8 m), we find T = 2pisqrt(0.8/9.81) ≈ 1.79 seconds. b) In a freely falling elevator, the acceleration due to gravity acts on both the elevator and the pendulum, so the period of the pendulum remains the same as on Earth, assuming no air resistance or other external factors.
The mass of a pendulum does not affect its period of oscillation. The period of a pendulum is determined by its length and the acceleration due to gravity. This means that pendulums with different masses but the same length will have the same period of oscillation.
The weight of the bob will determine how long the pendulum swings before coming to rest in the absence of applied forces. The period, or time of 1 oscillation, is determined only by the length of the pendulum.
Changing the length or mass of a pendulum does not affect the value of acceleration due to gravity (g). The period of a pendulum depends on the length of the pendulum and not on its mass. The formula for the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
The period of a pendulum is not affected by the mass of the pendulum bob. The period depends only on the length of the pendulum and the acceleration due to gravity.
No, the amplitude of a pendulum (the maximum angle it swings from the vertical) does not affect the period (time taken to complete one full swing) of the pendulum. The period of a pendulum depends only on its length and the acceleration due to gravity.
The period of a pendulum is independent of its mass but depends on the length of the pendulum and the acceleration due to gravity. A longer pendulum will have a longer period, while a shorter pendulum will have a shorter period. The period is also influenced by the angle at which the pendulum is released.
The formula for the period of a pendulum in terms of the square root of the ratio of the acceleration due to gravity to the length of the pendulum is T 2(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
Acceleration due to gravity affects the time period of a simple pendulum by increasing the speed at which the pendulum swings back and forth. A higher acceleration due to gravity results in a shorter time period for the pendulum to complete one full swing. This relationship is described by the formula T = 2π√(L/g), where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.