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When is the equation cotangent of x plus the square root of 3 equals 0 in the interval of 0 to 3pie?
First of all, it is pi, a letter of the Greek alphabet, not pie!
cot(x) + sqrt(3) = 0
cot(x) = -sqrt(3)
tan(x) = -1/sqrt(3)
The principal value is x = -pi/6c.
So the solutions are (-pi/6 + k*pi) radians where k is an integer: that is
k = 1 => 5*pi/6
k = 2 => 11*pi/6
k = 3 => 17*pi/6
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