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Its acceleration is always the same - the acceleration of gravity at 32 ft/sec/sec - no matter what distance it is during drop, until it hits the ground.

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Q: What is A ball is dropped from 5 m height What is its acceleration when it is at a height of 2.5 m?
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What is the acceleration of a kg ball thrown with a force of 25 N?

The acceleration of the ball can be calculated using Newton's second law, which states that acceleration is equal to the force applied divided by the mass of the object. In this case, the acceleration would be 25 N divided by the mass of the ball in kg.


If a ball takes 11 seconds to stop if dropped from 1 foot and 25 seconds from 2 feet how many seconds if dropped from 3 feet?

If we assume the time it takes for the ball to stop is directly proportional to the height it is dropped from, we can set up a proportion based on the given information. From the given data, we have the ratio of time to height as 11/1 = 25/2. Therefore, if we continue this ratio, the time it would take to stop if dropped from 3 feet would be 55 seconds.


What is the acceleration of a .30 kilogram ball if it's hit with a force of 25 newtons?

Using Newton's second law (F=ma), the acceleration of the ball can be calculated by dividing the force (25 N) by the mass of the ball (0.3 kg). The acceleration of the ball would be 83.3 m/s^2.


What is acceleration of 0.3 kg ball that hit with force of 25 N?

To find the acceleration of the ball, we can use Newton's second law of motion: ( F = ma ). Given that the force is 25 N and the mass is 0.3 kg, we can rearrange the formula to find the acceleration: ( a = \frac{F}{m} = \frac{25}{0.3} \approx 83.3 , m/s^2 ). The acceleration of the ball is approximately 83.3 m/s^2.


How much force it needed to accelerate a 25 kg bowling ball at?

The force needed to accelerate a 25 kg bowling ball would depend on the desired acceleration. Newton's second law states that force equals mass multiplied by acceleration (F = ma). If you specify the acceleration, the force required can be calculated using this formula.


What is the acclelerationof a 0.30 kilogram ball that is hit with a force of 25 newtons?

To find the acceleration of the ball, you need to use Newton's Second Law, which states that acceleration is equal to the force applied divided by the mass of the object. In this case, the acceleration of the 0.30 kilogram ball that is hit with a force of 25 Newtons would be 83.3 m/s^2.


How much force is needed to accelerate at 25 kg bowling ball at?

The force required to accelerate a 25 kg bowling ball can be calculated using the equation F = ma, where F is the force, m is the mass of the bowling ball, and a is the acceleration. If the acceleration is given, you can plug in the numbers to find the force needed.


What is the acceleration due to gravity if an object falls down from a height of 25 m?

The acceleration due to gravity is approximately 9.81 m/s^2 on Earth. When an object falls from a height of 25 m, it will experience this gravitational acceleration as it accelerates towards the ground.


What is the acceleration of a softball if it has a mass of 0.50 and hits the catchers glove with a force of 25 newtons?

At the point of impact, since force = mass x acceleration, acceleration = 25/0.5 = 50 N/kg If the catcher exerts a force of 25 newtons against the 0.5 kg ball, then he will cause it to accelerate at the rate of 50 m/sec-squared. If he happens to exert the force in the direction opposite to the velocity of the ball ... a common occurrence for a catcher ... then the acceleration is also opposite to the velocity of the ball, and the ball slows down.


What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?

Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2


How high will a basketball bounce if dropped?

If we knew from what height the ball, when dropped, would reach its terminal velocity, and if we knew the percentage of rebound the ball would give, we could then be certain. I can only guess that a basketball will rebound approximately 75% of the height from which it is dropped, and if the height at which it would reach terminal velocity is maybe 300 feet, the ball would bounce back up to 225 feet. Just a guess! A basketball has an elasticity (or "bounciness") of about 56 percent.I'm not sure there's a theoretical limit. In practice, of course, there would be one: when the velocity of the ball impacting the ground is so great the ball explodes rather than bouncing. But you'd have to fire it out of some kind of basketball cannon to get it moving that fast.The official standard for ball inflation is that the ball should bounce roughly 75% of its drop height (specifically, between 49" and 54") when dropped from 6 feet. If you're referring to just the height a dropped ball could bounce and you're not throwing it down with some kind of basketball-downward-hurling machine, you could calculate the theoretical bounce height by figuring out what terminal velocity is for a basketball, calculating how high you'd have to drop it from (assuming no atmosphere) to achieve that velocity, and then multiplying by 0.75. I'm not going to do it for you, because I'm not actually all that interested in the answer, but that's how you could do it if you are.


Jules kicks a soccer ball off the ground and in the air with an initial velocity of 25 feet per second Approximately what maximum height does the soccer ball reach?

1.6 ft