area of a parallelogram=base*height(base multiplied by height).
here "height" denotes the perpendicular distance between those two parallel sides one of which is taken as the base.
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
That depends upon what you know about the parallelogram. If you know the area and base length, then: area of parallelogram = base X height height =area / base If you know the lengths of the two pairs of parallel sides and the angles, then trigonometry can be used. If the height is required between one pair of sides, then: height = other_side_length / sine(angle_between_sides)
Area circle: π × radius² Area triangle: ½ × base × height Area Parallelogram: base × height Area: Rectangle: length × width In a triangle, the base is any side between two vertices and the height is the perpendicular distance from this side to the third vertex. In a parallelogram the base is any side. The height is the perpendicular distance between this side and the side parallel to it.
The area of a parallelogram is the base times the height; the height must be measured perpendicular to the base. If you correctly measure the height perpendicular to the base and you get different measurements, then you are NOT dealing with a parallelogram.
It is base*vertical distance between top and bottom (the perpendicular height).
The area of a parallelogram is base x height and the area of a triangle is 1/2 x base x height. So the area of a parallelogram will always be 2 times bigger than a triangle with the same base and height.
Its area is equal to its length, multiplied by its height
The formulae are quite similar; you multiply base x height, where the height is perpendicular to the base. In the case of a trapezium, you need to calculate the average of the two bases first.
It's the perpendicular distance between its lengths
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
That depends upon what you know about the parallelogram. If you know the area and base length, then: area of parallelogram = base X height height =area / base If you know the lengths of the two pairs of parallel sides and the angles, then trigonometry can be used. If the height is required between one pair of sides, then: height = other_side_length / sine(angle_between_sides)
Area circle: π × radius² Area triangle: ½ × base × height Area Parallelogram: base × height Area: Rectangle: length × width In a triangle, the base is any side between two vertices and the height is the perpendicular distance from this side to the third vertex. In a parallelogram the base is any side. The height is the perpendicular distance between this side and the side parallel to it.
The area of a parallelogram is the base times the height; the height must be measured perpendicular to the base. If you correctly measure the height perpendicular to the base and you get different measurements, then you are NOT dealing with a parallelogram.
It is base*vertical distance between top and bottom (the perpendicular height).
To find the area of a trapezoid using the area of a corresponding parallelogram, you can draw a line parallel to one of the bases of the trapezoid that extends to form a parallelogram. The area of the parallelogram is calculated using the formula (A = \text{base} \times \text{height}). Since the trapezoid shares the same height and one pair of parallel sides with the parallelogram, you can find the area of the trapezoid by subtracting the area of the triangular sections outside the trapezoid from the area of the parallelogram. This approach effectively utilizes the relationship between the two shapes to derive the trapezoid's area.
The height is the length of its altitude.
base*height