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Q: What is the relationship between the area of a parallelogram and the area of a trapezium?

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Suppose you have a trapezium whose parallel sides (bases) are of lengths A and B units, and where the height is h units If you flip a trapezium over and append it to the original along one of the bases you will have a parallelogram whose base is A+B units in length and whose height is h units. So 2*Area of trapezium = Area of parallelogram = (A + B)*h

area of a circle = area of a rectangle(parallelogram) formed by the sectors of circle with pi as length and radius as bradth.

The area of a parallelogram is base x height and the area of a triangle is 1/2 x base x height. So the area of a parallelogram will always be 2 times bigger than a triangle with the same base and height.

I don't know about the relation in the perimeters of a triangle and a parallelogram but if a triangle is on the same base on which the parallelogram is and the triangle is between the same parallel lines of the parallelogram, then the area of the triangle will be half the area of the parallelogram. That is, area of a triangle = 1/2 area of a parallelogram if the triangle is on the same base and between the same parallel lines.

Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.

area of a parallelogram=base*height(base multiplied by height).here "height" denotes the perpendicular distance between those two parallel sides one of which is taken as the base.

The area of a trapezium is given by 0.5*(a+b)*h where a and b are the lengths of the parallel sides and h is the vertical distance between them. The fact that the trapezium is isosceles does not matter. A trapezium is a 2 dimensional object and so it has no volume.

½×(sum of parallel sides)×(distance between them)

If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.

area of trapezium=1/2{a+b}h

Area = (1/2)*(sum of the parallel sides)*(distance between them)

Area = xy * sin A Where x is one length of the parallelogram, y is the other length and A is the angle between the two lines.

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