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When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what will be it maximum height?
'Maximum height' means the exact point at which the velocity changes from
upward to downward. At that exact point, the magnitude of the velocity is zero.
It doesn't matter what the velocity was when it left your hand. That number
determines the maximum height, but the velocity at that height is always zero.
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Thus using the formula: (vf)e2 = (vi)e2+2*a*d
vf = final velocity = 0 m/s
vi = initial velocity = 10 m/s
a = acceleration = gravity = - 9.81 m/s/s
d = displacement (distance) = ?
e is designating that the next figure is an exponent in the formula
So the formula is:
(0)e2 = (10)e2 + (2 * -9.81 * d)
0 = 100 + -19.62d
adding 19.62d to both sides of the equation
19.62d = 100
dividing by 19.62
d = ~ 5.097 meters
What else can I help you with?
If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
What is the condition for maximum velocity?
The condition for maximum velocity is acceleration equals zero; dv/dt = a= o.
What are the minimum and maximum requirements when drawing a triangle?
Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise.
What is the Maximum velocity for diesel?
90 degrees is the maximum velocity for diesel. Diesel is generally any liquid fuel used in diesel engines within vehicles.
How Determine the maximum wind velocity for a 45 crosswind if the maximum crosswind component for the airplane is 25 knots?
35 knots.
What is A football kicked off at an angle 20 from the ground reaches a maximum height of 4.7 m What is the initial velocity of the kick?
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
How can one determine the maximum height reached by an object launched with a given initial velocity?
To determine the maximum height reached by an object launched with a given initial velocity, you can use the formula for projectile motion. The maximum height is reached when the vertical velocity of the object becomes zero. This can be calculated using the equation: Maximum height (initial velocity squared) / (2 acceleration due to gravity) By plugging in the values of the initial velocity and the acceleration due to gravity (which is approximately 9.81 m/s2 on Earth), you can find the maximum height reached by the object.
How can you throw a projectile so that it has zero speed at the top?
To have zero speed at the top, you need to throw the projectile with an initial velocity such that it reaches its maximum height at that point. This requires the initial velocity to be exactly equal to the velocity that would be attained due to gravity when the projectile falls from that height. The angle of projection should be such that the vertical component of the initial velocity cancels out the velocity due to gravity.
Maria throws a ball straight up with an initial velocity of 10 m per s?
As the ball travels up, its velocity decreases until it reaches a maximum height and then starts to fall back down due to gravity. The initial velocity of the ball will determine how high it goes before falling back down.
What is the maximum height reached by a projectile shot straight up from the Earth's surface at a speed of 1.10104 km/hr?
The maximum height reached by a projectile shot straight up from the Earth's surface at a speed of 1.10104 km/hr is determined by the formula: Maximum height (initial velocity)2 / (2 acceleration due to gravity) Given that the initial velocity is 1.10104 km/hr, we can convert this to m/s by multiplying by 1000/3600. The acceleration due to gravity is approximately 9.81 m/s2. Plugging in the values, we can calculate the maximum height reached by the projectile.
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
What is the equation to calculate the maximum height of an object given an initial velocity and initial launch height?
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
When substrate concentration is equal to km what will be the initial velocity?
When the substrate concentration is equal to the Michaelis constant (Km), the initial velocity of the enzyme-catalyzed reaction will be half of the maximum velocity (Vmax) of the reaction. At Km, half of the enzyme active sites are filled with substrate, leading to half of maximum velocity being reached.
How does angle of projection affect the maximum height?
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
How can one determine the maximum height reached by a projectile?
To determine the maximum height reached by a projectile, you can use the formula: maximum height (initial vertical velocity)2 / (2 acceleration due to gravity). This formula calculates the height based on the initial vertical velocity of the projectile and the acceleration due to gravity.
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
