Wiki User
ā 14y agoIf the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
Wiki User
ā 14y agoAcceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
anything shot up with that initial velocity. There isn't anything in specific.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.
the answer is 24-9 m/sec. yuor welcome
1 meter/second/second in the same direction of travel
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
anything shot up with that initial velocity. There isn't anything in specific.
To find the initial velocity given an angle of 45 degrees and a distance of 10 meters, you can use the projectile motion equation for horizontal distance: x = Vā * cos(Īø) * t, where x is the horizontal distance, Vā is the initial velocity, Īø is the angle, and t is the time of flight. Since you know the angle and distance, you can solve for the initial velocity given those values.
To find the initial velocity of the box when it fell out, you can use the formula: final velocity squared = initial velocity squared + 2 * acceleration * distance. Given that the final velocity is 0 m/s, acceleration is 3 m/s^2, and distance is 24 meters, you can solve for the initial velocity.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Given the initial velocity (A), final velocity (B), and time (8 seconds), you can substitute the values into the formula to find the acceleration.
Problem: A football is kicked from the ground with an initial velocity of 20 m/s at an angle of 45 degrees above the horizontal. Determine the maximum height reached by the football. Answer: The maximum height can be found using the equation: H_max = (v^2 * sin^2(theta)) / (2g), where v is the initial velocity (20 m/s), theta is the launch angle (45 degrees), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in these values, the maximum height is calculated to be approximately 10.1 meters.
The initial velocity can be found using the kinematic equation: (d = v_0t + \frac{1}{2}at^2), where (d = 32m), (a = -9.81 m/s^2) (acceleration due to gravity), and (t) can be calculated using the time it takes for the rock to fall from a height of 450m. The initial velocity (v_0) is the horizontal component of velocity; therefore, it is the found by (v_0 = \frac{d}{t}).
In the usual simple treatment of projectile motion, the horizontal component of the projectile's velocity is assumed to be constant, and is equal to the magnitude of the initial (launch) velocity multiplied by the cosine of the elevation angle at the time of launch.
the answer is 24-9 m/sec. yuor welcome
The final velocity can be calculated using the formula: final velocity = initial velocity + (acceleration * time). If the initial velocity is 0 m/s, then the final velocity would be 10 m/s^2 * 7s = 70 m/s.