If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
anything shot up with that initial velocity. There isn't anything in specific.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.
the answer is 24-9 m/sec. yuor welcome
1 meter/second/second in the same direction of travel
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
anything shot up with that initial velocity. There isn't anything in specific.
Assuming you mean its range is 10m, then use the equation: v0 = sqrt(r*g/sin(2θ)), where r is its range, θ is its initial angle, and g is acceleration from gravity. =sqrt(10m*9.8m/s2/sin(90)) =sqrt(98.0m2/s2) =9.9m/s
To find the initial velocity of the box when it fell out, you can use the formula: final velocity squared = initial velocity squared + 2 * acceleration * distance. Given that the final velocity is 0 m/s, acceleration is 3 m/s^2, and distance is 24 meters, you can solve for the initial velocity.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Given the initial velocity (A), final velocity (B), and time (8 seconds), you can substitute the values into the formula to find the acceleration.
Problem: A football is kicked from the ground with an initial velocity of 20 m/s at an angle of 45 degrees above the horizontal. Determine the maximum height reached by the football. Answer: The maximum height can be found using the equation: H_max = (v^2 * sin^2(theta)) / (2g), where v is the initial velocity (20 m/s), theta is the launch angle (45 degrees), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in these values, the maximum height is calculated to be approximately 10.1 meters.
The initial velocity can be found using the kinematic equation: (d = v_0t + \frac{1}{2}at^2), where (d = 32m), (a = -9.81 m/s^2) (acceleration due to gravity), and (t) can be calculated using the time it takes for the rock to fall from a height of 450m. The initial velocity (v_0) is the horizontal component of velocity; therefore, it is the found by (v_0 = \frac{d}{t}).
the answer is 24-9 m/sec. yuor welcome
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
In the usual simple treatment of projectile motion, the horizontal component of the projectile's velocity is assumed to be constant, and is equal to the magnitude of the initial (launch) velocity multiplied by the cosine of the elevation angle at the time of launch.