When rolling a pair of dice there are 6∙6 = 36 possible outcomes.
The outcomes that give a sum of 5 are 4, [(1,4), (2,3), (3,2), (4,1)].
So the probability of not rolling a sum of 5 is:
P(NOT 5) = 1 - P(5) = 1 - 4/36 = 32/36 = 8/9 = 0.8888... ≈ 88.9%
Assuming these are regular dice, the probability is 1.
The probability is 35/36.
The probability is 8/36 or 2/9
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
The probability is 3/6 or 1/2
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
Assuming that the random variable is the sum of the two numbers rolled, the answer is 3/36 or 1/12.
There are 36 permutations of two dice. Of these, 9 have a sum of 5 or 6, so the probability of rolling a sum of 5 or 6 on two dice is 9 in 36, or 1 in 9, or about 0.1111.
Assuming these are regular dice, the probability is 1.
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
5 out of 12
It is 1/36.
The probability is 8/36 or 2/9
The probability is 35/36.
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
There is 4 ways to roll a 9 with 2 dice, and 36 possible outcomes. So, the probability of rolling a sum of 9 with two dice is 4/36 or 1/9.
The probability is 3/6 or 1/2