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Q: When x3 and y2 what is the area of the triangle?
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What is the area of a scalene triangle?

You can use matrices to find the area of the triangle.Find the three coordinates of the scalene triangle.(x1,y1)(x2, y2)(x3, y3).Then you substitute these numbers into this 3X3 matrix.x1 y1 1x2 y2 1x3 y3 1Find the determinant of this matrix.Then halve this answer and make it positive.This is your area of the triangle.The area of any triangle is: 0.5*base*perpendicular height


The curve with equation y2 equals x3 plus 3x2 is called the Tschirnhausen cubic?

y2=x3+3x2


How do you find the midpoint of a scalene triangle?

It makes no difference that the triangle is scalene. If the coordinates of the three vertices are (x1, y1), (x2, y2) and (x3, y3), then the coordinates of the midpoint (centroid) is [(x1 + x2 + x3)/3, (y1 + y2 + y3)/3]. Alternatively, join any two vertices to the midpoint of the opposite side. They (and the third median) will meet at the centroid.


How do you write median median line?

the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3


If 3 log x - 2 log y?

1


How do you factor x to the sixth minus y to the sixth?

x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)


What is the GCF of 12u7 y2 x3 and 16u6 x8?

4u6x3


How do you solve X9 - Y6 equals X3 - Y2 Between each X and Y power is an exponent?

2x2-y2


How do you factor x3 plus y3?

(x2 - xy + y2)(x + y)


How do you find the centroid of a triangle given the coordinates of the vertices?

The x-coordinate of the centroid is the arithmetic mean of the x-coordinates of the three vertices. And likewise, the y-coordinate of the centroid is the arithmetic mean of the y-coordinates of the three vertices. Thus, if A = (x1, y1), B = (x2, y2) and C = (x3, y3) then the coordinates of the centroid, G = [(x1,+ x2 + x3)/3, (y1 + y2 + y3)/3].


What is 8x2 y x3 y2 5y?

Assumption 8x2 = eight times x squared Assumption: x3 is x to the third Assumption: y2 is y squared Answer 40 y to the fourth x to the fifth = 40 y4 x5


What is the direct variation equation for x3 y2?

y = kx3/2If y2 varies directly with x3, then y varies directly with sqrt(x3) or x3/2.Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. If your question is not answered, please resubmit it, spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (x^2) or x-squared. :-)