It is not possible to answer the question with the information given - particularly with the form in which it is given.
It makes no difference that the triangle is scalene. If the coordinates of the three vertices are (x1, y1), (x2, y2) and (x3, y3), then the coordinates of the midpoint (centroid) is [(x1 + x2 + x3)/3, (y1 + y2 + y3)/3]. Alternatively, join any two vertices to the midpoint of the opposite side. They (and the third median) will meet at the centroid.
the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3
4u6x3
To translate a triangle 3 units left and 2 units up, you would subtract 3 from the x-coordinates of each vertex and add 2 to the y-coordinates. For example, if a triangle has vertices at (x1, y1), (x2, y2), and (x3, y3), the new vertices after translation would be (x1 - 3, y1 + 2), (x2 - 3, y2 + 2), and (x3 - 3, y3 + 2). This process shifts the entire triangle to its new position on the coordinate plane.
2x2-y2
You can use matrices to find the area of the triangle.Find the three coordinates of the scalene triangle.(x1,y1)(x2, y2)(x3, y3).Then you substitute these numbers into this 3X3 matrix.x1 y1 1x2 y2 1x3 y3 1Find the determinant of this matrix.Then halve this answer and make it positive.This is your area of the triangle.The area of any triangle is: 0.5*base*perpendicular height
In QBasic, you can color a triangle using the LINE statement to draw the triangle's sides and the PAINT statement to fill it with color. First, use LINE to specify the coordinates of the triangle's vertices. Then, use PAINT at one of the triangle's vertices with the desired fill color. For example: LINE (x1, y1)-(x2, y2), color LINE (x2, y2)-(x3, y3), color LINE (x3, y3)-(x1, y1), color PAINT (x1, y1), fillColor Replace (x1, y1), (x2, y2), (x3, y3) with the triangle's coordinates and color and fillColor with your chosen colors.
y2=x3+3x2
It makes no difference that the triangle is scalene. If the coordinates of the three vertices are (x1, y1), (x2, y2) and (x3, y3), then the coordinates of the midpoint (centroid) is [(x1 + x2 + x3)/3, (y1 + y2 + y3)/3]. Alternatively, join any two vertices to the midpoint of the opposite side. They (and the third median) will meet at the centroid.
the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3
1
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
4u6x3
To translate a triangle 3 units left and 2 units up, you would subtract 3 from the x-coordinates of each vertex and add 2 to the y-coordinates. For example, if a triangle has vertices at (x1, y1), (x2, y2), and (x3, y3), the new vertices after translation would be (x1 - 3, y1 + 2), (x2 - 3, y2 + 2), and (x3 - 3, y3 + 2). This process shifts the entire triangle to its new position on the coordinate plane.
2x2-y2
(x2 - xy + y2)(x + y)
The x-coordinate of the centroid is the arithmetic mean of the x-coordinates of the three vertices. And likewise, the y-coordinate of the centroid is the arithmetic mean of the y-coordinates of the three vertices. Thus, if A = (x1, y1), B = (x2, y2) and C = (x3, y3) then the coordinates of the centroid, G = [(x1,+ x2 + x3)/3, (y1 + y2 + y3)/3].