The square root of (9+9-9) equals 3.
Using the quadratic equation formula: x = -3 - the square root of 3 or x = -3 + the square root of 3
The cube root of the square root of π is the 6th root of π. ³√(√π) = 6√π. Using exponents, (π1/2)1/3 = π1/2 x 1/3 = π1/6
Using the symbol "^" for power. (-3)^1 * (-3)^(1/3) = (-3)^(4/3).
It is an irrational number and it is about 10.536 rounded to 3 decimal places
(3^3)*(11^3)=35937 so the cube root of 35937 using prime numbers is 3*11=33
The square root of (9+9-9) equals 3.
Yes. For example, the conjugate of (square root of 2 + square root of 3) is (square root of 2 - square root of 3).
147 49,3 7,7,3 The square root of 147 equals the square root of 49 times the square root of 3 which is 7 times the square root of 3.
hmm... okay, if I understand you correctly, 2 times the square root of 3 times the square root of 12? = 2(1.73)(3.46) = 11.9716. If you aren't using the approximations, then just simplifying is... [sorry, I can't do the square root sign on the computer...] 2(square root of 3)(square root of 12) = 2(square root of 3)(square root of 4*3) = 4(square root of 3)(square root of 3) = 4(3) = 12!!! HOPE I HELPED!! :-)
Using the quadratic equation formula: x = -3 - the square root of 3 or x = -3 + the square root of 3
The cube root of the square root of π is the 6th root of π. ³√(√π) = 6√π. Using exponents, (π1/2)1/3 = π1/2 x 1/3 = π1/6
Using the order of operations, the answer is 2 + sqrt(2).
-b +/- root b2 - 4ac / 2a(a = 3, b = -7, c = -3)7 +/- root -72 - 4 x 3 x -3 / 2 x 37 +/- root 49 + 36 / 67 +/- root 85 / 6
root 27 = root 9 x root 3 = 3 root 3. Dividing this by root 3 gives 3!
5 root 3
3 + square-root of 25