I don't understand your question but y=3x is the function of a graph, to graph the function you would plug points into the function such as x=0, x=1, x=-1 and you would find the y values at each point so that you can graph it. In this case the graph is a parabola which has a u shape.
No, it would not.
Since the function depends on 4 variables (assuming that p and P are the same variable), the full graph would require 5 dimensions. You can, however, graph something like a cross-section for the graph, in the sense that you keep most of the variables constant, and study the dependency of the function on a single variable at a time.
Yes, that is a shifted tanX graph, just as you would shift any graft.
It would have a downhill slope from left to right
I don't understand your question but y=3x is the function of a graph, to graph the function you would plug points into the function such as x=0, x=1, x=-1 and you would find the y values at each point so that you can graph it. In this case the graph is a parabola which has a u shape.
No, it would not.
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
It would be less steep
A deceleration graph typically shows a decreasing function where the value of deceleration is decreasing over time. This is in contrast to an acceleration graph, where the value of acceleration is typically constant or increasing over time. The deceleration graph would show negative values as the object slows down.
It would not touch or intersect the x-axis at all.
Since the function depends on 4 variables (assuming that p and P are the same variable), the full graph would require 5 dimensions. You can, however, graph something like a cross-section for the graph, in the sense that you keep most of the variables constant, and study the dependency of the function on a single variable at a time.
Both lines would be parallel to each but the y intercept would change from 5 to 9
Yes, that is a shifted tanX graph, just as you would shift any graft.
Yes, a position-time graph can have a negative slope. This would indicate that the object is moving in the negative direction with respect to the chosen reference point.
Given the function g(f(x)) = 2-x, you can find the domain as you would with any other function (i.e. it doesn't matter if it's composite). The output, however, has to be a real number. With this function, the domain is all real numbers. If you graph it, you see that the function is defined across the entire graph, wherever you choose to plot it.
This depends on what the graph represents. If it is a graph of velocity on the vertical and time on the horizontal, then if acceleration is at a constant rate, the graph will be a straight line with positive slope (pointing 'up'). If acceleration stops, then the graph will be a horizontal line (zero acceleration or deceleration). If it is deceleration (negative acceleration), then the graph will have negative slope (pointing down).