I don't understand your question but y=3x is the function of a graph, to graph the function you would plug points into the function such as x=0, x=1, x=-1 and you would find the y values at each point so that you can graph it. In this case the graph is a parabola which has a u shape.
y = 15 (by transitivity)
Their graphs are.
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
Slope=3, y-intercept=0. y=3x or y=3x+0
y = 3x + 1
3x - y = 4 Get y by itself to see if it is the same as y = 3x - 4: 3x = 4 + y 3x - 4 = y Therefore, 3x - y = 4 is the equivalent of y = 3x - 4.
y = 3x = 12y = 12
y = 15 (by transitivity)
-9
3x-y=9 y=3x-9
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
Algebraically rearrange both lines to ' y = ''' Hence y = 3x & 3y = x => y = (1/3)x Since the two lines are now y = 3x & y = (1/3)x The lines y = 3x has the greater/steeper slope at '3' , Whereas the other line has a slope of ' 1/3 '. (much less steep).
Their graphs are.
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
3x - y = 12 is the same as 3x - 12 = y, or y = 3x - 12.
Slope=3, y-intercept=0. y=3x or y=3x+0
3x+y=6