x2 -y2 =16
This is an equation that describes your problem.
We can write this equation as
(1/16)x2 -(1/16)y2 =1
You may recognize this as the equation whose graph is a hyperbola.
So there are an infinite number of solutions.
112 - 102 = 21
They are: 16 and 4
They are: 9-4 = 5
They are: 25-4 = 21
1 and 36 is one of two possible pairs -> so the squared numbers are 12 and 62
112 - 102 = 21
They are: 16 and 4
They are: 9-4 = 5
They are: 25-4 = 21
18 and 17.
1 and 36 is one of two possible pairs -> so the squared numbers are 12 and 62
The answer is 4 squared minus 2 squared as 4 squared is 16 minus 2 squared, which is 4, gives you 12 as an answer.
How about: 4-1 = 3 because 4 and 1 are square numbers
I assume you mean "squared" numbers?2² - 1² = 4 - 1 = 3
3 and 2, giving squares of 9 and 4.
3 squared and 2 squared.
9 and 25 (3)2 and (5)2