(x + 4)(2x + 3)
- 4X - 6X + 2 = 2(- 2X - 3X + 1) -------------------------that is all the factoring I can see to do here
The first equation factors to (3x + 2)(3x + 4) The second equation factors to (3a + 2b)(3a + 4b)
9x2+6x-8 = 0 (3x+4)(3x-2) = 0 Therefore: x = -4/3 or x = 2/3
3x + 2 = 3x + 6 This is not possible.
(x + 4)(2x + 3)
- 4X - 6X + 2 = 2(- 2X - 3X + 1) -------------------------that is all the factoring I can see to do here
- 3X - (- 4X) is the same as - 3X + 4X X(- 3 + 4) that is all the factoring needed there
If that's 3x2, the answer is (x + 1)(3x - 5)
The first equation factors to (3x + 2)(3x + 4) The second equation factors to (3a + 2b)(3a + 4b)
9x2+6x-8 = 0 (3x+4)(3x-2) = 0 Therefore: x = -4/3 or x = 2/3
(3x+1)(x-2)
Solve by factoring.2x2 - 3x + 1 = 0
No. It is 9x, which is a monomial.
2x3 + 8x2 + 3x + 12 = (2x3 + 8x2) + (3x + 12) = 2x2(x + 4) + 3(x + 4) = (x + 4)(2x2 + 3) Since you have asked this question I am assuming that you are not yet at a level where you might want (2x2 + 3) factorised into its imaginary factors.
3x + 2 = 3x + 6 This is not possible.
There are two ways to solve this, by factoring or the quadratic formula. I recommend factoring if possible because it is faster. -18x2 + 24x + 10 = 0 The first thing I see, is that I should factor out a -2 to make this problem more workable. -2(9x2 - 12x - 5) = 0 The -2 is now irrelevant, so I can cancel it and factor what remains. (3x + 1)(3x - 5) = 0 Now solve each separate equation for x to get two answers. 3x + 1 = 0, 3x = -1, x = -1/3 3x - 5 = 0, 3x = 5, x = 5/3 ANS: x= -1/3, 5/3