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Where are the points of intersection on the curves y equals 5x squared minus 2x plus 1 and y equals 6 minus 3x minus x squared?
So by definition both equations equal one another:
5x2-2x+1 = 6-3x-x2
5x2+x2-2x+3x+1-6 = 0
6x2+x-5 = 0
Factor the above equation with the help of the quadratic equation formula:
(6x-5)(x+1) = 0
When x = -1 y = 8
When x = 5/6 y = 101/36
Therefore the curves intersect at points: (-1, 8) and (5/6, 101/36)
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What are the point of intersection of x is equal to y squared plus 2y?
You need two, or more, curves for points of intersection.
What are the points of intersection of the line x -y equals 2 with x squared -4y squared equals 5?
The points of intersection are: (7/3, 1/3) and (3, 1)
What are the points of intersection of 3x -2y -1 equals 0 with 3x squared -2y squared equals -5 on the Cartesian plane?
Points of intersection work out as: (3, 4) and (-1, -2)
What is the place where 2 curves meet?
The points of intersection. The coordinates of such points will be the solutions to the simultaneous equations representing the curves.
What are the points of intersection of the line y equals -8-3x with the curve y equals -2-4x-x squared?
They work out as: (-3, 1) and (2, -14)
What are the point of intersection of x is equal to y squared plus 2y?
You need two, or more, curves for points of intersection.
What are the points of intersection of the line x -y equals 2 with x squared -4y squared equals 5?
The points of intersection are: (7/3, 1/3) and (3, 1)
What are the points of intersection of 3x -2y -1 equals 0 with 3x squared -2y squared equals -5 on the Cartesian plane?
Points of intersection work out as: (3, 4) and (-1, -2)
Where are the points of intersection of the equations 4y squared -3x squared equals 1 and x -2y equals 1?
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
What is the place where 2 curves meet?
The points of intersection. The coordinates of such points will be the solutions to the simultaneous equations representing the curves.
What are points of intersection of the line 3x -y equals 5 with the curve of 2x squared plus y squared equals 129?
Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)
What are the points of intersection of the line y equals -8-3x with the curve y equals -2-4x-x squared?
They work out as: (-3, 1) and (2, -14)
What are the points of intersection of y equals x squared plus 2x plus 2 with y equals x cubed plus 2?
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)
What are the points of intersection of the parabolas of y equals 4x squared -12x -3 and y equals x squared plus 11x plus 5 on the Cartesian plane?
The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)
What are the points of intersection of x plus y equals 7 with x squared plus y squared equals 25 showing key stages of work?
If: x+y = 7 and x2+y2 = 25 Then: x = 7-y and so (7-y)2+y2 = 25 => 2y2-14y+24 = 0 Solving the quadratic equation: y = 4 and y = 3 By substitution points of intersection: (3, 4) and (4, 3)
How many points of intersection are the between x2 and x2 plus 5?
There are none. Those two curves do not intersect.
Where are the points of intersection on the x axis when y equals 8x squared -26x plus 15?
(3/4, 0) and (5/2, 0) Solved with the help of the quadratic equation formula.
