If: 2x+y = 0 and x+y = -4
Then: x = 4 and y = -8
Possible steps:
2x + y = 0
x + y = -4
Subtract the two equations:
x = 4
Plug x back in to one equation and solve for y:
4 + y = -4
y = -8
By graphing the lines on the coordinated plane they will intersect at (2, -4) which is the solution of the equations
-2x+16 = 0 -2x = -16 x = 8
many solutions
2x + 2x + 146 + 26 = 172 4x + 172 = 172 4x = 0 x = 0
(2x + 3)(2x + 3)
x=0
x = 0
By graphing the lines on the coordinated plane they will intersect at (2, -4) which is the solution of the equations
2x = -7 - 8y
If -2x +14 = 0, -2x = -14, or x = 7.
-2x+16 = 0 -2x = -16 x = 8
If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
Assuming that 4x2+2x = 0: 2x (2x+1) = 0 2x = 0 or 2x+1 = 0 x = 0 or -1/2
many solutions
y= -2x
2x + 2x + 146 + 26 = 172 4x + 172 = 172 4x = 0 x = 0
(2x + 3)(2x + 3)