To find the transverse axis of the hyperbola given by the equation ( y^2 - 25x^2 = 100 ), we first rewrite it in standard form: ( \frac{y^2}{100} - \frac{x^2}{4} = 1 ). This equation indicates that the hyperbola is oriented vertically, with its center at the origin (0, 0). The transverse axis is vertical and extends along the y-axis, with its length determined by the value of ( a ) (which is 10 in this case, since ( a^2 = 100 )). Thus, the transverse axis is along the line ( y = \pm 10 ).
If it's written like this (6+4)(6+4) - (25x2) Then the answer will be: 10x10 - 50 100 - 50 = 50
so, the formula is Length times 2 plus Width times 2 equals perimeter or Lx2+wx2=P 25x2+25x2 50+50=100 so, your answer would be 100
100<2x50<2x25<5x5 100<4x25<5x5 5x5=25x2=50x2=100 5x5=25x4=100
How many are you expecting ? How will you know if we give you all of them,or only some of them ?Since the highest power of the variable in the equation is '2', ("x2"),the equation has exactly two solutions.25x2 - 100 = 0Divide each side by 25:x2 - 4 = 0Add 4 to each side:x2 = 4Take the square root of each side:x = +4 and -4And there are your two solutions.
is the x a variable? because it would be impossible to solve with that information. in not then 150 25*2-5*-20 50--100 (negative and negative equal positive) 150 25x2 - 5x - 20 = 0 (5x + 1)(5x - 5) = 0 therefore; x = -1, or x = 1/5
If it's written like this (6+4)(6+4) - (25x2) Then the answer will be: 10x10 - 50 100 - 50 = 50
so, the formula is Length times 2 plus Width times 2 equals perimeter or Lx2+wx2=P 25x2+25x2 50+50=100 so, your answer would be 100
100<2x50<2x25<5x5 100<4x25<5x5 5x5=25x2=50x2=100 5x5=25x4=100
How many are you expecting ? How will you know if we give you all of them,or only some of them ?Since the highest power of the variable in the equation is '2', ("x2"),the equation has exactly two solutions.25x2 - 100 = 0Divide each side by 25:x2 - 4 = 0Add 4 to each side:x2 = 4Take the square root of each side:x = +4 and -4And there are your two solutions.
is the x a variable? because it would be impossible to solve with that information. in not then 150 25*2-5*-20 50--100 (negative and negative equal positive) 150 25x2 - 5x - 20 = 0 (5x + 1)(5x - 5) = 0 therefore; x = -1, or x = 1/5
150/25=6 25x4=100 + 25x2=50
How much is ( (6+4)(5+5) ) - (25x2)? go by BEDMASB= BracketsE= ExponentsD= DivisionM= MultiplicationA= AddingS= SubtractionFirst do the first brackets. ( (6+4)(5+5) )6+4=105+5=10(10)(10)see how the brackets are close together (the stuff in bold)? That means Multiplication. 10 x 10 = 100Now do the second brackets (25x2). 25 x 2 = 50Now re write the equation ( 100 ) - ( 50 )Now just remove the brackets. And change the signs. (If it was to be - 50 then it would be + 50. But since its a positive then you leave it alone)100 - 50 = 50
25x1=25 25x2=50 25x3=75 25x4=100 25x5=125 25x6=150 25x7=175 25x8=200 25x9=225 25x10=250
100
If you mean on the axis where it has /\/ to skip from for example 0 to 100, 110, 120 because there is no need for the 0-100 then it's called a broken axis.[ Tilde ~ ]
They touch each other at (0, 100) on the x and y axis.
This would mean that on a graph, a change of 100 on the x axis would be accompanied by a change of 1 on the y axis.