it is an expression
No, if there is a sqaured variable, the equation is not linear.
To determine which linear expression is a factor of a given polynomial function, you typically need to perform polynomial division or use the Factor Theorem. If you can substitute a root of the polynomial into the linear expression and obtain a value of zero, then that linear expression is indeed a factor. Alternatively, if you have the polynomial's roots, any linear expression of the form ( (x - r) ), where ( r ) is a root, will be a factor. Please provide the specific polynomial function for a more accurate response.
It is a linear expression.
It is a linear expression in two variables. As an expression it cannot be solved. Furthermore, to solve equations in two variables you need at least two linear equations.
it is an expression
A screw jack typically has one degree of freedom, which allows linear motion along the axis of the screw. However, some designs may have additional degrees of freedom depending on the specific mechanical configuration.
No, if there is a sqaured variable, the equation is not linear.
It isa linear expression,a binomial expression,an algebraic expression,a polynomial expression.
No, it could be a constant.
To determine which linear expression is a factor of a given polynomial function, you typically need to perform polynomial division or use the Factor Theorem. If you can substitute a root of the polynomial into the linear expression and obtain a value of zero, then that linear expression is indeed a factor. Alternatively, if you have the polynomial's roots, any linear expression of the form ( (x - r) ), where ( r ) is a root, will be a factor. Please provide the specific polynomial function for a more accurate response.
I think the word you're looking for is "exponential". A linear expression is of the form ax + b whereas an exponential expression is of the form x^a + b.
It is a linear expression.
It is a linear expression.
It is a linear expression in two variables.
Without an equality sign the given expression can't be considered to be a linear equation.
It is a linear expression in two variables. As an expression it cannot be solved. Furthermore, to solve equations in two variables you need at least two linear equations.