7-4-14
7
The coordinates of every one of the infinitely many points on the line defined by the equation is a solution.
There are many different ordered pairs for this. To figure it out, make up a value for x. Then plug it into the equation and solve to find y. You can use any number. For example, if x=2, then your equation would be 3(2)+1. Solve that and you get 7 for the answer (y). if x=2, then y=7 so one of the ordered pairs would be (2,7).
(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4
10
7-4-14
The ordered pair (0, -6) Ordered pairs look like (x, y). they are the coordinates of a point on your graph. Asking if (0,6) is a solution to your equation means, does this point lie on the graph? Or algebraically, if you substitute in x = 0 and y = -6 into the equation, does it work? y = 5x-7 -6 = 5(0) -7 -6 = 0 - 7 -6 = -7 Well, -6 does NOT = -7, so we know that this ordered pair is not a solution to the function.
3
x = 5 and y = 4
Without an equality sign the given terms can't be considered to be a straight line equation.
7
The coordinates of every one of the infinitely many points on the line defined by the equation is a solution.
Use this cordinate ,find the other cordinate that makes the ordered pair a solution of the given equation: x+4y=7,(_,3)
The inverse of an ordered pair (a,b) is the pair (b,a). So you simply switch the order.
The center of the circle is at (-7, 5)
There are an infinite number of ordered pairs. (-5, -7) is one pair