The ordered pair (0, -6)
Ordered pairs look like (x, y). they are the coordinates of a point on your graph.
Asking if (0,6) is a solution to your equation means, does this point lie on the graph?
Or algebraically, if you substitute in x = 0 and y = -6 into the equation, does it work?
y = 5x-7
-6 = 5(0) -7
-6 = 0 - 7
-6 = -7
Well, -6 does NOT = -7, so we know that this ordered pair is not a solution to the function.
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If an ordered pair is a solution to a system of linear equations, then algebraically it returns the same values when substituted appropriately into the x and y variables in each equation. For a very basic example: (0,0) satisfies the linear system of equations given by y=x and y=-2x By substituting in x=0 into both equations, the following is obtained: y=(0) and y=-2(0)=0 x=0 returns y=0 for both equations, which satisfies the ordered pair (0,0). This means that if an ordered pair is a solution to a system of equations, the x of that ordered pair returns the same y for all equations in the system. Graphically, this means that all equations in the system intersect at that point. This makes sense because an x value returns the same y value at that ordered pair, meaning all equations would have the same value at the x-coordinate of the ordered pair. The ordered pair specifies an intersection point of the equations.
y = (x + 2)2 andy = (2x)2(x-2)2 + (y-16)2 = 0
In the context of Cartesian coordinates, the ordered pair (0, 0) represents a point at the intersection of the x-axis and the y-axis, also known as the origin. The first number in the ordered pair (0) represents the x-coordinate, which is the distance along the horizontal axis from the origin. The second number (0) represents the y-coordinate, which is the distance along the vertical axis from the origin. Therefore, the ordered pair (0, 0) indicates a position where both the x and y coordinates are zero, placing the point at the origin of the coordinate plane.
x = 0 is the y-axis
For example, if you have (0, 6) or (3, 1). Which of them is a solution to y - 2x = 6? Check (0, 6): y - 2x = 6, substitute 0 for x, and 6 for y into the equation 6 - 2(0) =? 6 6 - 0 =? 6 6 = 6 True, then (0, 6) is a solution. Check (3, 1): y - 2x = 6, substitute 3 for x, and 1 for y into the equation 1 - 2(3) =? 6 1 - 6 =? 6 -5 = 6 False, then (3, 1) is not a solution.