To find the equation of the line passing through the points (3, 20) and (-9, 6), we first calculate the slope (m) using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{6 - 20}{-9 - 3} = \frac{-14}{-12} = \frac{7}{6}). Using the point-slope form (y - y_1 = m(x - x_1)), we can use one of the points, say (3, 20), to get the equation: (y - 20 = \frac{7}{6}(x - 3)). Simplifying this gives the line's equation in slope-intercept form.
The equation is x = 2
Points: 0 2 and 6 0 Equation: y = -1/3x+2
The formula for a line is: Y = mX + b
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
y = -1.125x + 2.25
y=-x
Points: (3, 2) and (-9, 6) Slope: -1/3 Equation: 3y = -x+9
The equation is x = 2
Points: 0 2 and 6 0 Equation: y = -1/3x+2
The formula for a line is: Y = mX + b
x = 2
The equation of the line passing through the points (mx, ny) and (2, 5) is y ((5-ny)/(2-mx))x (5 - ((5-ny)/(2-mx))2).
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
Points: (2, 2) and (3, 1) Slope: -1 Equation: y = -x+4
6666
y = -1.125x + 2.25
y = 4