The formula for a line is:
Y = mX + b
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
If a line has an undefined slope, it is vertical. The equation of a vertical line passing through the point (13) is written as ( x = 13 ). This indicates that for all points on the line, the x-coordinate remains constant at 13, while the y-coordinate can take any value.
It is: y = 5x+6
Points: (5, -2) and (4, 3)Slope: -5Equation: y = -5x+23
This starts with the collocation circle to go through the three points on the curve. First write the equation of a circle. Then write three equations that force the collocation circle to go through the three points on the curve. Last, solve the equations for a, b, and r.
Y=4x+3
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
x = 1
y=mx+c where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis). that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
Points: (-3, -4) and (6, -1) Slope: 1/3 Equation: 3y = x-9
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
Slope-intercept form
It is: y = 5x+6
Points: (2, 5) and (4, 3) Slope: -1 Equation: y = -x+7 in slope-intercept form --- If you want to write the slope-intercept form of the equation of the line passing through the given points, then use the two points to find the slope of the line. After that, use the slope and one of the points to find the y-intercept. For instance, m = (5 - 3)/(2 - 4) = 2/-2 = -1(the slope) y = mx + b (replace m with -1, and (x, y) with (4, 3)) 3 = -1(4) + b 3 = -4 + b (add 4 to both sides) 7 = b Thus, y = -x + 7 is the equation of the line passing through (2, 5) and (4, 3).
Points: (5, -2) and (4, 3)Slope: -5Equation: y = -5x+23
the Equation of a Line Given That You Know Two Points it Passes Through.
y=-3x-2