To find the equation of a line with a slope of 2 that passes through the point (0, 3), you can use the slope-intercept form of a line, which is ( y = mx + b ). Here, ( m ) is the slope and ( b ) is the y-intercept. Since the point (0, 3) indicates that the y-intercept ( b ) is 3, the equation of the line is ( y = 2x + 3 ).
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
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A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
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Y+2 = 2 (x-3)
General formula
2
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Assuming the point is (9, -4), the equation is y = -4.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
The equation is: y = 4x-22
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
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The equation works out as: y = 5x+7
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.