9/x
The English expression for the quotient of nine and the sum of a number and one is "nine divided by the sum of a number and one." This can also be written mathematically as ( \frac{9}{x + 1} ), where ( x ) represents the number.
Nine less than the quotient of two and a number ( x ) can be expressed mathematically as ( \frac{2}{x} - 9 ). This represents the result of dividing 2 by ( x ) and then subtracting 9 from that quotient.
The expression for the sum of ten and the quotient of a number ( x ) and 666 can be written as ( 10 + \frac{x}{666} ). This represents adding 10 to the result of dividing ( x ) by 666.
x/3
It could be x/16 or 16/x. The x could be substituted by any other letter, for example, y/16 or 16/y.
An expression that represents the quotient of a number and 7 can be written as "x/7" where x is the number. This expression signifies dividing the number x by 7. In algebraic terms, it represents a fraction where the numerator is the number being divided and the denominator is 7.
The algebraic expression for "4 decreased by the quotient of a number and 7" can be represented as 4 - (x/7), where x is the variable representing the number. The expression first calculates the quotient of the number and 7 by dividing x by 7, and then subtracts that quotient from 4. This expression captures the mathematical operation described in the question.
The expression for the sum of ten and the quotient of a number ( x ) and 666 can be written as ( 10 + \frac{x}{666} ). This represents adding 10 to the result of dividing ( x ) by 666.
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
x/3
It could be x/16 or 16/x. The x could be substituted by any other letter, for example, y/16 or 16/y.
Restate the question: "What is the quotient of 35 and -x as an expression?"If this is not your question, please clarify and ask the question again. :-)35/(-x) = -35/x
Hi
To find the quotient when (2x^2 + 3x - 9) is divided by (x^3), we note that the degree of the divisor (x^3) is greater than the degree of the dividend (2x^2 + 3x - 9). Therefore, the quotient is (0) since (x^3) cannot divide (2x^2 + 3x - 9) without resulting in a fractional expression.
x/8
x+2=
x/15