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Q: Which factorization can be used to identify the real zeros of the function f(x) -20x2 23x-6?

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20x2 = 41x+9 20x2-41x-9 = 0 (5x+1)(4x-9) = 0 Therefore: x = -1/5 or x = 9/4

20x2=40

X3 - 20X2 + 19Xfactor out an XX(X2 - 20X + 19)what two factors of 19 add up to - 20?X(X - 1)(X - 19)============ fully factored

If the quotient of a certain binomial and 20x2 is is the polynomial

(20x + 3)(1x + 1)

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20x2=40

20x2 = 41x+9 20x2-41x-9 = 0 (5x+1)(4x-9) = 0 Therefore: x = -1/5 or x = 9/4

20x2=40

20x2 + 22xy + 6y2 = 20x2 + 10xy + 12xy + 6y2 = 10x(2x + y) + 6y(2x + y) = (2x + y)(10x + 6y) = 2(2x + y)(5x + 3y)

10(2x^2 + 3)

X3 - 20X2 + 19Xfactor out an XX(X2 - 20X + 19)what two factors of 19 add up to - 20?X(X - 1)(X - 19)============ fully factored

-(5x - 2)(4x - 3)

If the quotient of a certain binomial and 20x2 is is the polynomial

-31-8x if the first and second x is a multiplication sign.

From 1 July 20x1 - 30 June 20x2

(20x + 3)(1x + 1)

2(5x + 3y)(2x + 5y)