20x2 + 22xy + 6y2 = 20x2 + 10xy + 12xy + 6y2 = 10x(2x + y) + 6y(2x + y)
= (2x + y)(10x + 6y) = 2(2x + y)(5x + 3y)
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A: 3x-2y = 1 => 3x = 1+2y B: 3x2-2y2+5 = 0 => 3x2 = 2y2-5 Square both sides in equation A: 9x2 = 1+4y+4y2 Multiply all terms by 3 in equation B: 9x2 = 6y2-15 So it follows that:- 6y2-15 = 1+4y+4y2 and 6y2-15-1-4y-4y2 = 0 Collect like terms: 2y2-4y-16 = 0 Divide all terms by 2: y2-2y-8 = 0 Factorise: (y-4)(y+2) = 0 Therefore: y = 4 or y = -2 Substitute the above y values into the linear equation to find the values of x: The points of intersection are: (3, 4) and (-1,-2)
mathematics: to combine terms that are alike
I guess your two equations are:4x - 6y = 22x + 3y = 12Since the plus (+) and equals (=) signs have been stripped from your question.If this is the case, then they are not parallel since their gradients are not the same.Without working them out exactly, it can be seen that one is positive (equation 1.) and the other is negative (equation 2.):4x - 6y = 2 ⇒ 6y = 4x - 2 ⇒ +ve gradient2x + 3y = 12 ⇒ 3y = -2x + 12 ⇒ -ve gradient
The answer to 6y times y is 6y^2. This is because when you multiply two terms with the same base (y in this case), you add the exponents. In this case, the exponent on y is 1 for both terms, so 1 + 1 = 2, giving us y^2. The coefficient 6 remains unchanged in the final answer.