any number
3
True
Change all the signs. Suppose you have the quadratic equation: y = ax2 + bx + c Its additive inverse is -ax2 - bx - c.
fx=5x1 / 9
29
f(x) = bX is not an exponential function so the question makes no sense.
If the quadratic function is f(x) = ax^2 + bx + c then its inverse isf'(x) = [-b + +/- sqrt{b^2 - 4*(c - x)}]/(2a)
y=x
in general, the y-intercept of the function f(X)= axb^x is the point__.
The logarithm function. If y = bx, then x = by is the inverse --> y = logb(x). If b = 10, then the function is often stated with the '10' implied: just log(x). For natural logarithms (y = ex), the function y = ln(x) [which indicates loge(x)] is the inverse.
a constant
any number
The fx-991MS lacks the inverse operator so the matrix inverse is not possible, Try 991Es instead
3
True
Depending on the domain and range, the inverse may or may not be defined. Assuming it is defined, the inverse function can be derived as follows: The negative parabola is y = -ax2 + bx + c (where a>0) so that -ax2 + bx + c - y = 0 using the quadratic formula, x = [-b ± sqrt(b2 + 4*a*(c-y)]/(-2a) which is a square root function, and will be real provided that b2 + 4*a*(c-y) > 0