f(x) = bX is not an exponential function so the question makes no sense.
The horizontal asymptote for y = 0 when the degree is greater than the denominator, resulting in the inability to do long division.
If you mean y = 2^x, then no, it is not a linear equation. This is an exponential equation. The graph of this exponential equation would start out near zero on the left-hand side (there is a horizontal asymptote at y = 0) and would gradually increase as you move to the right: overall, it has a curved shaped. If you mean y = 2x, then yes, it is a linear equation.
The domain of the function f(x) = (x + 2)^-1 is whatever you choose it to be, except that the point x = -2 must be excluded. If the domain comes up to, or straddles the point x = -2 then that is the equation of the vertical asymptote. However, if you choose to define the domain as x > 0 (in R), then there is no vertical asymptote.
Yes. Take the functions f(x) = log(x) or g(x) = ln(x) In both cases, there is a vertical asymptote where x = 0. Because a number cannot be taken to any power so that it equals zero, and can only come closer and closer to zero without actually reaching it, there is an asymptote where it would equal zero. Note that transformations (especially shifting the function left and right) can change the properties of this asymptote.
Asymptote's occur when your equation has a denominator of zero Holes may occur when your equation has both a numerator and denominator of zero So... The equation for the denominator equals zero is: x2-x-2 = 0 The equation for both the numerator and denominator equals zero is x - 2 = x2-x-2 = 0 For interests sake... lets solve it. ---- x2-x-2 = 0 (x+1)(x-2) = 0 x = -1, 2 x - 2 = x2-x-2 = 0 x - 2 = 0 x = 2 A vertical asymptote occurs at x = -1 A vertical asymptote or hole may appear at x = 2
True
asymptote
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
It will have the same asymptote. One can derive a vertical asymptote from the denominator of a function. There is an asymptote at a value of x where the denominator equals 0. Therefore the 3 would go in the numerator when distributed and would have no effect as to where the vertical asymptote lies. So that would be true.
2x-2/x^2+3x-4
x-axis
If the question is, Is y = x4 an exponential function ? then the answer is no.An exponential function is one where the variable appears as an exponent.So, y = 4x is an exponential function.
x axis
yes
One point on a logarithmic graph is not sufficient to determine its parameters. It is, therefore, impossible to answer the question.
no
Assuming that b > 0, it is an inverse power function or an inverse exponential function.