21 x 2 has greatest perimeter
Quadratic equation: 9x2-21x+12.25 = 0 Area: 36.75 square cm
9x-21x = -12
Let the sides be x+10.5 and x:- Using Pythagoras: (x+10.5)^2 +x^2 = 25.5^2 So: x^2 +21x +110.25 +x^2 = 650.25 Transposing terms: 2x^2 +21x -540 = 0 Using the quadratic equation formula gives x a positive value of 12 Perimeter: 12+(12+10.5)+25.5 = 60 cm
21x + 9 = 180 21x = 180 - 9 21x = 171 x = 171/21 x = 8.143
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
Quadratic equation: 9x2-21x+12.25 = 0 Area: 36.75 square cm
9x-21x = -12
Let the sides be x+10.5 and x:- Using Pythagoras: (x+10.5)^2 +x^2 = 25.5^2 So: x^2 +21x +110.25 +x^2 = 650.25 Transposing terms: 2x^2 +21x -540 = 0 Using the quadratic equation formula gives x a positive value of 12 Perimeter: 12+(12+10.5)+25.5 = 60 cm
21x + 9 = 180 21x = 180 - 9 21x = 171 x = 171/21 x = 8.143
21x+452 = 32-84x 21x+84x = 32-452 105x = -420 x = -4
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
If: 9x = 21x-3 Then: x = 1/4 or 0.25
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
Make it equal zero by subtracting 21x from both sides. 20x2 - 21x - 5 factors to (4x - 5)(5x + 1)
2x2+21x+49 = (2x+7)(x+7)
7x
9