The person or program that solves the equation does.
The solutions are (4n - 1)*pi/2 for all integer values of n.
Cosec x = -2 => sin x = -0.5 The primary solution is x = -pi/6 radians. Therefore the solutions are: 2n*pi - pi/6 and (2n+1)*pi + pi/6 for all integer n.
Solutions may be closed or open regions or they may be points within a region (for example, grid points for integer solutions), or points of intersection between curves or between curves and the axes. It all depends on what the graphs and the solutions are.
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
The person or program that solves the equation does.
This equation describes all the points on the unit sphere. There is an infinite number of solutions. Some quick integer solutions would be (1,0,0) and (0,1,0) and (0,0,1) which are the one the axes.
The solutions are (4n - 1)*pi/2 for all integer values of n.
Cosec x = -2 => sin x = -0.5 The primary solution is x = -pi/6 radians. Therefore the solutions are: 2n*pi - pi/6 and (2n+1)*pi + pi/6 for all integer n.
The question cannot be answered since it contains no inequality.
Solutions may be closed or open regions or they may be points within a region (for example, grid points for integer solutions), or points of intersection between curves or between curves and the axes. It all depends on what the graphs and the solutions are.
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
No. 3/(1/7) is a rational number. However, (1/7) cannot be used as an integer. Incidentally, the number equals 21.
Yes. By definition a multiple of 8 is any number that can be expressed as 8*n, where n is an integer. But 8n=4*(2*n), and 2*n is an integer, when n is an integer. Because 8n equals four times an integer, 8n is a multiple of 4.
You may be able to give a formula that represents all the solutions. For example, the equation sin(x) = 0 where x is real, has infinitely many solutions but they can be summarised, very simply, as x = n*pi radians (180*n degrees) where n is any integer. Some solution sets are harder to summarise.You may be able to give a formula that represents all the solutions. For example, the equation sin(x) = 0 where x is real, has infinitely many solutions but they can be summarised, very simply, as x = n*pi radians (180*n degrees) where n is any integer. Some solution sets are harder to summarise.You may be able to give a formula that represents all the solutions. For example, the equation sin(x) = 0 where x is real, has infinitely many solutions but they can be summarised, very simply, as x = n*pi radians (180*n degrees) where n is any integer. Some solution sets are harder to summarise.You may be able to give a formula that represents all the solutions. For example, the equation sin(x) = 0 where x is real, has infinitely many solutions but they can be summarised, very simply, as x = n*pi radians (180*n degrees) where n is any integer. Some solution sets are harder to summarise.
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
4.87