A multiple
Itself because 1 times a number = the same number
Yes. Every non-zero number is divisible by itself.
1.0070 has 5 significant figures. This is because when you are looking at a number with a decimal number, you start from the left and find a non-zero number. When you find the non-zero number, every number after it is significant.
The common denominator refers to a multiple that is COMMON to two or more numbers. You have only one number in the question! The common denominator for a number is any non-zero multiple of the number.
Not necessarily. A number is also a multiple of itself.
No. Every non-zero whole number is a multiple of 1.
The two factors of every non-zero number are 1 and the number itself.
A multiple
1 times a number equals itself. The number is the first on the list of multiples.
I'm not sure what you want. You can have 5 and 2 and any non-zero whole number. You can have 10 and any two non-zero whole numbers. You can have any even number, then any multiple of 5, then any non-zero whole number. Or any multiple of ten, then any two non-zero whole numbers. I think I covered the possibilities.
Every number is divisible by any non-zero number. Whether or not it is evenly divisible depends on the value of Y.
Itself because 1 times a number = the same number
1
You multiply the fraction by any non-zero multiple of its denominator.
Every other non-zero integer.
Not in the normal usage of the words. Usually, a number is considered to be a multiple of another number only of there is an integer you can multiply the other number by in order to get the first number. If you allowed multiplication by non-integers, then every number would be a multiple of every other number except zero and the term "multiple" would be fairly useless. So in the normal way of speaking, 39 is not a multiple of 6 because there is no integer (whole number) you can multiply 6 by in order to get 39.