Yes. Every non-zero number is divisible by itself.
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102 is divisible by: 1 2 3 6 17 34 51 102.
102 For a number to be divisible by 6, it must be divisible by both 2 and 3. 102 div by 2 = 51; 102 div by 3 = 17
Yes, 102 divided by 2 = 51.
102 as 102/2 = 51 102/3 = 34
Yes but it will have a remainder of 2