If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
Yes, it is the only solution.
r=0 is the solution...
According to my calculations, yes. 2x+8=3x+11 -8 2x=3x+3 -2x 0=x+3 -3 -3=x
3x2 + 2x - 8 = 0 is a quadratic equation.
Yes.
It is a linear equation in x. The equation has the solution x = 0.
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
x = 0 and y = 4
4x2 - 4x + 1 = 0 => (2x - 1)(2x - 1) = 0 => (2x - 1)2 = 0 There is one solution: x = 1/2. It is a repeated root of the equation.
Yes, it is the only solution.
r=0 is the solution...
According to my calculations, yes. 2x+8=3x+11 -8 2x=3x+3 -2x 0=x+3 -3 -3=x
2x + 14 = 0Subtract 14 from each side of the equation: 2x = -14Divide both sides of the equation by 2: x = -7You can also obtain solutions to equations by visting wolframalpha.com. Enter solve 2x+14=0, for example. You can click on the 'step-by-step' button to see how the equation was solved.
3x2 + 2x - 8 = 0 is a quadratic equation.
There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 ± 0.330719*i where i is the imaginary square root of -1.
Multiply First equation by 2: 6y - 2x = 0Add second equation to this: 6y - 2x + 2x + 2y = 0 + 7Simplify: 8y = 7 so y = 0.875 and x = 2.625