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What is 5r equals 25?
5r = 25 is a linear equation in one variable, r. The solution is r = 5.
What is 6r plus 2 equals 2?
To solve the equation 6r + 2 = 2, you need to isolate the variable r. Start by subtracting 2 from both sides of the equation. This will give you 6r = 0. To solve for r, divide both sides of the equation by 6. The solution is r = 0.
18-6r equals 0 What does r equal?
Divide both sides by 6: 3 - r = 0, so r = 3 satisfies the equation.
What is 16 subtract r equals negative sixteen?
It's a linear equation in 'r' . Here's how to find the solution:16 - r = -16Add 16 to each side of the equation:32 - r = 0Add 'r' to each side:32 = r
Solve the equation 8 equals r-5?
13
What is r times 1 equals 1?
It is a linear equation in one variable r. The solution to the equation is r = 1.
What is 5r equals 25?
5r = 25 is a linear equation in one variable, r. The solution is r = 5.
What is 6r plus 2 equals 2?
To solve the equation 6r + 2 = 2, you need to isolate the variable r. Start by subtracting 2 from both sides of the equation. This will give you 6r = 0. To solve for r, divide both sides of the equation by 6. The solution is r = 0.
Is r equals 9 a solution of 128 equals 16r?
No, it is not. Substitute and check. You have 128 + 16r. So now, if r=9, then the equation would be 128 = 16x9. But, 16x9 is 145 and is not equal to 128. Thus, r=9 is not the solution. The solution is r+ 128/16 which is equal to 8. Thus, the actual solution is r = 8.
18-6r equals 0 What does r equal?
Divide both sides by 6: 3 - r = 0, so r = 3 satisfies the equation.
What is 16 subtract r equals negative sixteen?
It's a linear equation in 'r' . Here's how to find the solution:16 - r = -16Add 16 to each side of the equation:32 - r = 0Add 'r' to each side:32 = r
Solve the equation 8 equals r-5?
13
What is the radius of the circle with the equation x² plus y² equals 36?
A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6
R plus s equals 4 2r plus 3s equals 8?
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
In the equation r 14 equals 39 what is the value of r?
25
What is 8 equals 6 r 5?
It is an equation in the variable r.
How does one solve the differential equation y double prime plus y prime plus y equals zero?
Let y=ce^(rx). R^2+r+1=0. Quadratic equation to find R.
