To find the equation of a circle with center ((2, -1)) that passes through the point ((3, 4)), we first calculate the radius. The radius (r) is the distance between the center and the point, which is given by (r = \sqrt{(3 - 2)^2 + (4 - (-1))^2} = \sqrt{1^2 + 5^2} = \sqrt{26}). The standard equation of a circle is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center. Thus, the equation is ((x - 2)^2 + (y + 1)^2 = 26).
A cord that passes through the center of a circle is a diameter of that circle. And you've probably guessed that this is the largest cord of that circle.
Neither secant nor tangent pass through the center of a circle. A secant passes through one point on the circle and the tangent passes through two points on a circle.
A chord that passes through the center of a circle is its diameter.
diameter
A secant is a line that passes through a point on the circle and the center of the circle. It intersects the circle at two different points.
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A diameter is a segment that passes through the center of a circle and has both endpoints on the circle.
A cord that passes through the center of a circle is a diameter of that circle. And you've probably guessed that this is the largest cord of that circle.
The secant of a circle passes through the center of a circle sometimes
Neither secant nor tangent pass through the center of a circle. A secant passes through one point on the circle and the tangent passes through two points on a circle.
yes a diameter passes through the center of a circle
A chord that passes through the center of a circle is its diameter.
It is the diameter of the circle.
diameter
The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4
A secant is a line that passes through a point on the circle and the center of the circle. It intersects the circle at two different points.
(x-5)2 + y2 = 17