The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2
Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2
r^2=4
The equation of the circle is x^2+(y-2)^2=4
9
That's the equation of a circle with its center at the origin and a radius of 8.
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
The distance from any point on the circle to the origin
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
9
x2 + y2 = 64
x² + y² = 81.
x² + y² = 4.
x2 + y2 = 16
x2 + y2 = 81
x2 + y2 = 49
x2 + y2 = r2, where r is the radius.
It is x2 + y2 = 4
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
x2 + y2 = 2