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The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2

Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2

r^2=4

The equation of the circle is x^2+(y-2)^2=4

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โˆ™ 2009-03-23 16:42:33
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Q: Find an equation of the circle that has center 0 2 and passes through the origin.?
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