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Q: Find an equation of the circle that has center 0 2 and passes through the origin.?

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9

That's the equation of a circle with its center at the origin and a radius of 8.

The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.

The distance from any point on the circle to the origin

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

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The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100

x2 + y2 = 64

x2 + y2 = 16

x2 + y2 = 81

x² + y² = 81.

x² + y² = 4.

9

x2 + y2 = r2, where r is the radius.

It is x2 + y2 = 4

x2 + y2 = 49

A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1

x2 + y2 = 2

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