It depends. They weigh equally if 2 blocks weigh as much as 1 marble.
If 2 blocks are heavier, 10 blocks > 5 marbles
If 1 marble is heavier, 10 blocks < 5 marbles
6/10 or 3/5
1/5 of 10 = 2.
20% of 50 marbles is 1 fifth of the marbles in the bag. so 50 marbles divided by 5 =10 blue marbles
It is (1/2)5 = 1/32
To find the probability of drawing two red marbles from a bag containing three red marbles and two green marbles (a total of five marbles), you can use the combination formula. The number of ways to choose 2 red marbles from 3 is ( \binom{3}{2} = 3 ), and the total ways to choose 2 marbles from 5 is ( \binom{5}{2} = 10 ). Thus, the probability of drawing two red marbles is ( \frac{3}{10} ) or 0.3.
6/10 or 3/5
5/10
1/5 of 10 = 2.
20% of 50 marbles is 1 fifth of the marbles in the bag. so 50 marbles divided by 5 =10 blue marbles
It is (1/2)5 = 1/32
Probability = number_of_white_marbles / total_number_of_marbles = 10 / (4 + 6 + 4 + 10) = 10 / 24 = 5/12 ~= 0.42
4:10 or 2:5
3 in 10
To find the probability of drawing two red marbles from a bag containing three red marbles and two green marbles (a total of five marbles), you can use the combination formula. The number of ways to choose 2 red marbles from 3 is ( \binom{3}{2} = 3 ), and the total ways to choose 2 marbles from 5 is ( \binom{5}{2} = 10 ). Thus, the probability of drawing two red marbles is ( \frac{3}{10} ) or 0.3.
put one cup into another cup, then put 5 marbles in each.
20% (or 2 in 10 chance)
To find the probability of drawing a marble with the number 5 on it, we first note that there are 10 marbles in total, each uniquely numbered from 2 to 11. Since only one of these marbles has the number 5, the probability is calculated as the number of favorable outcomes (1) divided by the total number of outcomes (10). Thus, the probability is ( \frac{1}{10} ) or 0.1.