A1
The 'A' series of paper is such that A0 is 1m2 in area and each next number up is half the previous area: A1 is 0.5m2, A2 is 0.25m2 and so on.
The ratio of the sides of the paper series are such that 1 Sheet of A0 can be cut in half parallel to its shorter side to create 2 sheets of A1; each sheet of A1 can be cut in half parallel to its shorter side to create 2 sheets of A2; and so on.
The sides are in the ratio of 1 : sqrt(2). A0 is approx 841mm x 1189mm, A1 is approx 595mm x 841mm, A2 is approx 420mm x 595mm, A3 is approx 297mm x 420mm, A4 is approx 210mm x 297mm, and so on.
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A0 is twice the size of A1 A1 is twice the size of A2 A2 is twice the size of A3 A3 is twice the size of A4 A4 is twice the size of A5 A5 is twice the size of A6 And so on
an=an-1 To use this formula, you start of with a value on the first term, but theoretical, it'd turn out like this: a1=a1-1=a0 a2=a2-1=a1 a3=a3-1=a2 a4=a4-1=a3 a5=a5-1=a4 Where a0 would be your starting term (this formula is based on the previous term, and that's why you must have a value to start off with).
There are infinitely many numbers.For example, if(5.2 + 5.5)/2 = a1(5.2 + a1)/2 = a2(5.2 + a2)/2 = a3(5.2 + a3)/2 = a4 and so on,then each element of the infinite sequence, a1, a2, a3, ... meets the requirements.
A1 paper size measures 594 mm x 841 mm, while A4 paper size measures 210 mm x 297 mm. Since A1 is four times the size of A2, which in turn is four times the size of A3, A4 can fit into A1 a total of 8 times when arranged properly. Thus, you can fit 8 A4 sheets into one A1 sheet.
Consider the sequence(2 + 2.7)/2 = a1,(2 + a1)/2 = a2(2 + a2)/2 = a3(2 + a3)/2 = a4, etc,then every member of the infinite sequence a1, a2, a3, ... meets the requirements.