an=an-1
To use this formula, you start of with a value on the first term, but theoretical, it'd turn out like this:
a1=a1-1=a0
a2=a2-1=a1
a3=a3-1=a2
a4=a4-1=a3
a5=a5-1=a4
Where a0 would be your starting term (this formula is based on the previous term, and that's why you must have a value to start off with).
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
the value of the exponent n1
The sum of the first 10 positive integers, using the formula N1 + (N1 + 1) + ... + N2 = N2 * (N2 + 1) / 2 - (N1 - 1) * N1 / 2 is: 55
I have my math final tomorrow and I don't remember the quick method to finding the r value when they are not consecutive terms, please help me. n1=1/81, n3=1/3
You subtract the exponents. N30 - N1 = N30 - 1 = N29.You subtract the exponents. N30 - N1 = N30 - 1 = N29.You subtract the exponents. N30 - N1 = N30 - 1 = N29.You subtract the exponents. N30 - N1 = N30 - 1 = N29.
He's at the top of HadesIsle, accessible from the outside, only during N1. There are five questions, which are relatively easy. To make life easier, save before starting his quiz, and through trial and error you'll get the N1 FolderA, which is widely regarded as the best N1 ExtraFolder for the N1 quarterfinals.
They are reverse operations, in the sense that if y is the square of x then x is a square root of y. Remember though, that in the above scenario, -x is also a square root of y.
Well, well, well, looks like we're playing a little game of "let's mess with the numbers." This sequence seems to be jumping all over the place like a kangaroo on a sugar rush. Let's break it down: 25, 26, 24, 27, 23. Looks like each number is just doing its own thing, no rhyme or reason.
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
The N1 is a rocket.
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2-1) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
the value of the exponent n1
the value of the exponent n1
void main() { int i; float n1,n2; abc: printf("Enter two nos "); scanf("%f%f",&n1,&n2); printf("\n %f + %f = %f " ,n1,n2,n1+n2); printf("\n %f - %f = %f " ,n1,n2,n1-n2); printf("\n %f x %f = %f " ,n1,n2,n1*n2); printf("\n %f / %f = %f " ,n1,n2,n1/n2); printf("\npress 5 to make another calculation"); scanf("%d",&i); if (i==5) goto abc; }
The sum of the first 10 positive integers, using the formula N1 + (N1 + 1) + ... + N2 = N2 * (N2 + 1) / 2 - (N1 - 1) * N1 / 2 is: 55
what are the price of a movie ticket at N1 city