31 (the rest are all multiples of 3).
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The number that doesn't belong in the sequence is 123. The pattern among the other numbers is that they are all prime numbers, specifically 3, 31, and 27 (which is a prime cube). However, 123 is not a Prime number as it can be divided by 3 and 41.
27 doesn't belong because it rounds up and all the other numbers round down.
31 or 123
Suppose the smaller number is x, then the bigger number is x+7 Their sum is 123 ie x + (x+7) = 123 or 2x + 7 = 123 or 2x = 123 - 7 = 116 so that x = 58 and then x+7 = 65 The two numbers are 58 and 65
Let a be the first number and b the second number then, (1) a = 8 + 2b and (2) a + b =123 From (2) a = 123 - b substituting for a in (1) gives :- 123 - b = 8 + 2b , 3b = 115, b = 115/3 = 38⅓. and substituting for this in (2) gives :- a + 38⅓ = 123, a = 123 - 38⅓ = 84⅔. So, a = 84⅔ and b = 38⅓
123 123 123
First number: x Second: x+1 Third: x+2 x + x+1 + x+2 = 123, 3x + 3 = 123 x + 1 = 41 x = 40 x + 2 = 42 The numbers are: 40, 41, 42.
Let x be the smallest number to be solved:x + (x+1) + (x+2) = 1233x + 3 = 1233x = 123 - 3 = 120x = 120 / 3 = 40 is the smallest numberand 40 + 41 + 42 = 123