There are 20, 2-digit integers that have both of there digits as even: 20, 22, 24, 26, 28, 40, 42, 44, 46, 48, 60, 62, 64, 66, 68, 80, 82, 84, 86, 88.
If you lift the constraint of the number itself only being able to have 2 digits, then there are an infinite amount of numbers with 2 even digits in them, as you can string together two of the following numbers, 0, 2, 4, 6, and 8, with as many odd numbers as you wish.
Finally, to answer your question in the discussion section, there are an infinite number of even numbers. This is because there are an infinite number of integers, and 2 X any integer is necessarily even.
two
There are 41 of them.
28
it can be 22 44 66 or 88, yes that is true, but it can also be 20 22 24 26 28, and so on because the person clearly says that the number has two digits and both digits are even, but the person did not say that the even numbers had to be the same
The only two digit numbers whose digits add up to 17 are 89 and 98. Since 98 is an even number, 89 is prime.
two
There are 41 of them.
28
Zero.
Since there are two multiples of 5, and plenty of even numbers, the last two digits are 00.
98,764
it can be 22 44 66 or 88, yes that is true, but it can also be 20 22 24 26 28, and so on because the person clearly says that the number has two digits and both digits are even, but the person did not say that the even numbers had to be the same
Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.
The only two digit numbers whose digits add up to 17 are 89 and 98. Since 98 is an even number, 89 is prime.
It is even. Both numbers end with odd digits and two odd digits always add to an even number. You can see that is the case in this instance.377 + 87 = 464
998 - 3 digits even number Next even number is 1000 - 4 digits. So 998 is the largest ...
1348.