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There are 20, 2-digit integers that have both of there digits as even: 20, 22, 24, 26, 28, 40, 42, 44, 46, 48, 60, 62, 64, 66, 68, 80, 82, 84, 86, 88.
If you lift the constraint of the number itself only being able to have 2 digits, then there are an infinite amount of numbers with 2 even digits in them, as you can string together two of the following numbers, 0, 2, 4, 6, and 8, with as many odd numbers as you wish.
Finally, to answer your question in the discussion section, there are an infinite number of even numbers. This is because there are an infinite number of integers, and 2 X any integer is necessarily even.
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How many two digits numbers are there in which the product of the digits is even?
two
How many two digit even numbers are there which have different digits?
There are 41 of them.
What is your number.your number has two digits and both digits are even The sum of your numbers digits is 10 your number has 4 as a factor. The difference between the two digits of my number is 6?
28
What number are you your number has two digits and both digits are even?
it can be 22 44 66 or 88, yes that is true, but it can also be 20 22 24 26 28, and so on because the person clearly says that the number has two digits and both digits are even, but the person did not say that the even numbers had to be the same
You are a prime number you have two digits The sum of your digits are 17 what number are you?
The only two digit numbers whose digits add up to 17 are 89 and 98. Since 98 is an even number, 89 is prime.
